|z-1|=1

Lösung

∣ z - 1 ∣ = 1

z = 0 or z = 2

Schritte zur Lösung

∣ z - 1 ∣ = 1

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

z - 1 = - 1 or z - 1 = 1

z - 1 = - 1 or z - 1 = 1

z = 0 or z = 2

6 (x - 5) = 4 x + 20

f a c t or x^{2} + 3 x + 5 x + 15

6 x - 3 (x + 8) = 9

s im pl i f y \frac{\frac{1}{y} - \frac{1}{x}}{\frac{1}{x ^{2}} + \frac{1}{y ^{2}}}

t^{2} - 6 t + 9 = 0