n^2-9n+8=0

解

n^{2} - 9 n + 8 = 0

n = 8, n = 1

解答ステップ

n^{2} - 9 n + 8 = 0

解くとthe二次式

n_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 8 = 7

n_{1, 2} = \frac{- ( - 9 ) \pm 7}{2 \cdot 1}

解を分離する

n_{1} = \frac{- ( - 9 ) + 7}{2 \cdot 1}, n_{2} = \frac{- ( - 9 ) - 7}{2 \cdot 1}

n = \frac{- ( - 9 ) + 7}{2 \cdot 1} : 8

n = \frac{- ( - 9 ) - 7}{2 \cdot 1} : 1

二次equationの解:

n = 8, n = 1