faktorisieren-2a^3b^3+a^6+b^6

Lösung

faktorisieren

- 2 a^{3} b^{3} + a^{6} + b^{6}

(a - b)^{2} (a^{2} + ab + b^{2})^{2}

Schritte zur Lösung

- 2 a^{3} b^{3} + a^{6} + b^{6}

Klammere aus

- 1 : - (2 a^{3} b^{3} - a^{6} - b^{6})

= - (2 a^{3} b^{3} - a^{6} - b^{6})

Faktorisiere

2 a^{3} b^{3} - a^{6} - b^{6} : (a - b) (a^{2} + ab + b^{2}) (b - a) (b^{2} + ab + a^{2})

= - (a - b) (a^{2} + ab + b^{2}) (b - a) (b^{2} + ab + a^{2})

Vereinfache

- (a - b) (a^{2} + ab + b^{2}) (b - a) (b^{2} + ab + a^{2}) : - (a - b) (b - a) (a^{2} + ab + b^{2})^{2}

= - (a - b) (b - a) (a^{2} + ab + b^{2})^{2}

Vereinfache

- (a - b) (b - a) (a^{2} + ab + b^{2})^{2} : (a - b)^{2} (a^{2} + ab + b^{2})^{2}

= (a - b)^{2} (a^{2} + ab + b^{2})^{2}

s im pl i f y \frac{1}{3} \cdot (- 9)

s im pl i f y - (\frac{7}{2})^{2}

96 \div 12

s im pl i f y - 5 y^{2}

s im pl i f y \frac{1}{5 ^{4}}