(\partial)/(\partial t)((z)(s^2t-st^{27}))

解答

\frac{\partial}{\partial t} ((z) (s^{2} t - s t^{27}))

z (s^{2} - 27 s t^{26})

求解步骤

\frac{\partial}{\partial t} ((z) (s^{2} t - s t^{27}))

将

z, s

视为常数

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= z \frac{\partial}{\partial t} (s^{2} t - s t^{27})

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (\frac{\partial}{\partial t} (s^{2} t) - \frac{\partial}{\partial t} (s t^{27}))

\frac{\partial}{\partial t} (s^{2} t) = s^{2}

\frac{\partial}{\partial t} (s t^{27}) = 27 s t^{26}

= z (s^{2} - 27 s t^{26})

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