展开 (y(-y^4+16y^2+8y-32))/8

解答

展开

\frac{y ( - y ^{4} + 16 y ^{2} + 8 y - 32 )}{8}

- \frac{y ^{5}}{8} + 2 y^{3} + y^{2} - 4 y

求解步骤

\frac{y ( - y ^{4} + 16 y ^{2} + 8 y - 32 )}{8}

乘开

y (- y^{4} + 16 y^{2} + 8 y - 32) : - y^{5} + 16 y^{3} + 8 y^{2} - 32 y

= \frac{- y ^{5} + 16 y ^{3} + 8 y ^{2} - 32 y}{8}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- y ^{5} + 16 y ^{3} + 8 y ^{2} - 32 y}{8} = - \frac{y ^{5}}{8} + \frac{16 y ^{3}}{8} + \frac{8 y ^{2}}{8} - \frac{32 y}{8}

= - \frac{y ^{5}}{8} + \frac{16 y ^{3}}{8} + \frac{8 y ^{2}}{8} - \frac{32 y}{8}

数字相除:

\frac{16}{8} = 2

= - \frac{y ^{5}}{8} + 2 y^{3} + \frac{8 y ^{2}}{8} - \frac{32 y}{8}

数字相除:

\frac{8}{8} = 1

= - \frac{y ^{5}}{8} + 2 y^{3} + y^{2} - \frac{32 y}{8}

数字相除:

\frac{32}{8} = 4

= - \frac{y ^{5}}{8} + 2 y^{3} + y^{2} - 4 y

s im pl i f y (x^{2} - 9 x \circ x - 9) (- 2)

s im pl i f y (b - a) (b + a)

e x p an d - 2 y y^{'} (x) + (x - y^{2}) y^{'} (x)

e x p an d sin (λ - \frac{π}{3}) + cos (λ + \frac{π}{6})

e x p an d (2 x^{2} - \frac{3}{x})^{4}