erweitern pi(2x+1)^2(2x-1)

Lösung

erweitern

π (2 x + 1)^{2} (2 x - 1)

8 π x^{3} + 4 π x^{2} - 2 π x - π

Schritte zur Lösung

π (2 x + 1)^{2} (2 x - 1)

Wende das Distributivgesetz an:

a (b - c) = ab - a c

a = π (2 x + 1)^{2}, b = 2 x, c = 1

= π (2 x + 1)^{2} \cdot 2 x - π (2 x + 1)^{2} \cdot 1

= 2 π x (2 x + 1)^{2} - 1 π (2 x + 1)^{2}

Vereinfache

2 π x (2 x + 1)^{2} - 1 π (2 x + 1)^{2} : 8 π x^{3} + 4 π x^{2} - 2 π x - π

= 8 π x^{3} + 4 π x^{2} - 2 π x - π

e x p an d \frac{2 e ^{x^{2}} ( x ^{2} - 1 )}{x ^{3}}

e x p an d (5 x^{\frac{1}{2}} + 3) (5 x^{\frac{1}{2}} - 3)

e x p an d - \frac{x + 1}{( x - 1 ) ^{3}}

e x p an d sin (x) (tan (x) + csc (x))

e x p an d + (x + x y) d y