t^2-6t-40=0

解

t^{2} - 6 t - 40 = 0

t = 10, t = - 4

解答ステップ

t^{2} - 6 t - 40 = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 40) = 14

t_{1, 2} = \frac{- ( - 6 ) \pm 14}{2 \cdot 1}

解を分離する

t_{1} = \frac{- ( - 6 ) + 14}{2 \cdot 1}, t_{2} = \frac{- ( - 6 ) - 14}{2 \cdot 1}

t = \frac{- ( - 6 ) + 14}{2 \cdot 1} : 10

t = \frac{- ( - 6 ) - 14}{2 \cdot 1} : - 4

二次equationの解:

t = 10, t = - 4