p^2+6p-16=0

解

p^{2} + 6 p - 16 = 0

p = 2, p = - 8

解答ステップ

p^{2} + 6 p - 16 = 0

解くとthe二次式

p_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 16) = 10

p_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 1}

解を分離する

p_{1} = \frac{- 6 + 10}{2 \cdot 1}, p_{2} = \frac{- 6 - 10}{2 \cdot 1}

p = \frac{- 6 + 10}{2 \cdot 1} : 2

p = \frac{- 6 - 10}{2 \cdot 1} : - 8

二次equationの解:

p = 2, p = - 8