16x^2+56x+49=0

解

16 x^{2} + 56 x + 49 = 0

x = - \frac{7}{4}

十進法表記

x = - 1.75

解答ステップ

16 x^{2} + 56 x + 49 = 0

解くとthe二次式

x_{1, 2} = \frac{- 56 \pm 5 6 ^{2} - 4 \cdot 16 \cdot 49}{2 \cdot 16}

5 6^{2} - 4 \cdot 16 \cdot 49 = 0

x_{1, 2} = \frac{- 56 \pm 0}{2 \cdot 16}

x = \frac{- 56}{2 \cdot 16}

\frac{- 56}{2 \cdot 16} = - \frac{7}{4}

x = - \frac{7}{4}

二次equationの解:

x = - \frac{7}{4}