zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

6(x-1)=x^2+x

解答

6 (x - 1) = x^{2} + x

解答

x = 3, x = 2

求解步骤

6 (x - 1) = x^{2} + x

展开

6 (x - 1) : 6 x - 6

6 x - 6 = x^{2} + x

交换两边

x^{2} + x = 6 x - 6

将

6

para o lado esquerdo

x^{2} + x + 6 = 6 x

将

6 x

para o lado esquerdo

x^{2} - 5 x + 6 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

x = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

x = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

二次方程组的解是:

x = 3, x = 2

作图

流行的例子

2 = x^{2} - 3 x - 8

4= 4/3 (x-6)34(x-6)

4 = \frac{4}{3} (x - 6) 34 (x - 6)

solvefor t,S= 1/2 at^2

so l v e f or t, S = \frac{1}{2} a t^{2}

- 9 x^{2} + 24 x - 16 = 0

solvefor y,4y^2-3x=-4(x-5)

so l v e f or y, 4 y^{2} - 3 x = - 4 (x - 5)