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受欢迎的代数 >

9p^2+272p+944=0

解答

9 p^{2} + 272 p + 944 = 0

解答

p = - 4, p = - \frac{236}{9}

+1

十进制

p = - 4, p = - 26.22222 \dots

求解步骤

9 p^{2} + 272 p + 944 = 0

使用求根公式求解

p_{1, 2} = \frac{- 272 \pm 27 2 ^{2} - 4 \cdot 9 \cdot 944}{2 \cdot 9}

27 2^{2} - 4 \cdot 9 \cdot 944 = 200

p_{1, 2} = \frac{- 272 \pm 200}{2 \cdot 9}

将解分隔开

p_{1} = \frac{- 272 + 200}{2 \cdot 9}, p_{2} = \frac{- 272 - 200}{2 \cdot 9}

p = \frac{- 272 + 200}{2 \cdot 9} : - 4

p = \frac{- 272 - 200}{2 \cdot 9} : - \frac{236}{9}

二次方程组的解是:

p = - 4, p = - \frac{236}{9}

作图

流行的例子

2 x^{2} + 5 x = 1200

(1 + x)^{2} + x^{2} = 11

12 x + 9 = - 4 x^{2}

5 t^{2} - 11 t = 12

x+3x+1.5x44x-2=169

x + 3 x + 1.5 x 44 x - 2 = 169