solvefor b,2=q+f/b

解答

求解

b, 2 = q + \frac{f}{b}

b = \frac{f}{2 - q}; q \neq = 2

求解步骤

2 = q + \frac{f}{b}

将

q

para o lado esquerdo

2 - q = \frac{f}{b}

在两边乘以

b

2 b - q b = f

分解

2 b - q b : b (2 - q)

b (2 - q) = f

两边除以

2 - q; q \neq = 2

b = \frac{f}{2 - q}; q \neq = 2

so l v e f or x, \frac{- y}{x + 1} (2) = 3

\frac{6}{f} - \frac{10}{3 f} = 2

879200 = \frac{405}{b ^{2}}

\frac{2 x + 3}{15 x - 6} = \frac{5}{9}

\frac{9 - x ^{2}}{x ^{2} + 3 x} = - 1