(a+1/a)^2=3

Lösung

(a + \frac{1}{a})^{2} = 3

a = \frac{3}{2} + \frac{1}{2} i, a = - \frac{3}{2} - \frac{1}{2} i, a = \frac{3}{2} - \frac{1}{2} i, a = - \frac{3}{2} + \frac{1}{2} i

Schritte zur Lösung

(a + \frac{1}{a})^{2} = 3

Vereinfache

(a + \frac{1}{a})^{2} : a^{2} + 2 + \frac{1}{a ^{2}}

a^{2} + 2 + \frac{1}{a ^{2}} = 3

Multipliziere beide Seiten mit

a^{2}

a^{4} + 2 a^{2} + 1 = 3 a^{2}

Löse

a^{4} + 2 a^{2} + 1 = 3 a^{2} : a = \frac{3}{2} + \frac{1}{2} i, a = - \frac{3}{2} - \frac{1}{2} i, a = \frac{3}{2} - \frac{1}{2} i, a = - \frac{3}{2} + \frac{1}{2} i

a = \frac{3}{2} + \frac{1}{2} i, a = - \frac{3}{2} - \frac{1}{2} i, a = \frac{3}{2} - \frac{1}{2} i, a = - \frac{3}{2} + \frac{1}{2} i

\frac{( x ^{4} - 1 )}{( x ^{3} )} = 0

\frac{( N + 1 ) !}{( N - 1 ) !} = 56

\frac{9}{1} = \frac{100}{x}

305 = \frac{1}{x ( 175 )}

2 = \frac{x + 11}{x - 9}