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人気のある代数 >

solvefor f,f^{-1}(x)=x^4+2

解

解く

f, f^{- 1} (x) = x^{4} + 2

解

f = \frac{x}{x ^{4} + 2}; x \neq = \frac{1}{2 ^{\frac{1}{4}}} + \frac{1}{4 2} i, x \neq = - \frac{1}{4 2} - \frac{1}{4 2} i, x \neq = - \frac{1}{2 ^{\frac{1}{4}}} + \frac{1}{4 2} i, x \neq = \frac{1}{4 2} - \frac{1}{4 2} i

解答ステップ

f^{- 1} (x) = x^{4} + 2

改良

\frac{x}{f} = x^{4} + 2

以下で両辺を乗じる:

f

x = x^{4} f + 2 f

辺を交換する

x^{4} f + 2 f = x

因数

x^{4} f + 2 f : f (x^{4} + 2)

f (x^{4} + 2) = x

以下で両辺を割る

x^{4} + 2; x \neq = \frac{1}{2 ^{\frac{1}{4}}} + \frac{1}{4 2} i, x \neq = - \frac{1}{4 2} - \frac{1}{4 2} i, x \neq = - \frac{1}{2 ^{\frac{1}{4}}} + \frac{1}{4 2} i, x \neq = \frac{1}{4 2} - \frac{1}{4 2} i

f = \frac{x}{x ^{4} + 2}; x \neq = \frac{1}{2 ^{\frac{1}{4}}} + \frac{1}{4 2} i, x \neq = - \frac{1}{4 2} - \frac{1}{4 2} i, x \neq = - \frac{1}{2 ^{\frac{1}{4}}} + \frac{1}{4 2} i, x \neq = \frac{1}{4 2} - \frac{1}{4 2} i

グラフ

人気の例

7 = \frac{6}{x} + 5

solvefor s,n= L/(p(r+s))

so l v e f or s, n = \frac{L}{p ( r + s )}

20+10[ 2/(2+m)]=22.2

20 + 10 [\frac{2}{2 + m}] = 22.2

solvefor x,y=(3x(y+3))/x

so l v e f or x, y = \frac{3 x ( y + 3 )}{x}

-2.7=(5-t)/(t^2-9)

- 2.7 = \frac{5 - t}{t ^{2} - 9}