(4x+1)/(2(8x+6))=2(4x+3)

解答

\frac{4 x + 1}{2 ( 8 x + 6 )} = 2 (4 x + 3)

x = - \frac{47}{64} + i \frac{3 7}{64}, x = - \frac{47}{64} - i \frac{3 7}{64}

求解步骤

\frac{4 x + 1}{2 ( 8 x + 6 )} = 2 (4 x + 3)

在两边乘以

2 (8 x + 6)

4 x + 1 = 4 (4 x + 3) (8 x + 6)

解

4 x + 1 = 4 (4 x + 3) (8 x + 6) : x = - \frac{47}{64} + i \frac{3 7}{64}, x = - \frac{47}{64} - i \frac{3 7}{64}

x = - \frac{47}{64} + i \frac{3 7}{64}, x = - \frac{47}{64} - i \frac{3 7}{64}

0.00005 = \frac{8}{x ^{4}}

so l v e f or x, y = - \frac{y}{x}

\frac{3 x - 5}{2 x ^{2} - x - 3} = 0

2 = \frac{1}{1 + x e ^{- 1}}

\frac{18}{x} = \frac{96}{141}