2^{x+1}=3

Lösung

2^{x + 1} = 3

x = \frac{ln ( 3 )}{ln ( 2 )} - 1

Dezimale

x = 0.58496 \dots

Schritte zur Lösung

2^{x + 1} = 3

Wende Exponentenregel an

(x + 1) ln (2) = ln (3)

Löse

(x + 1) ln (2) = ln (3) : x = \frac{ln ( 3 )}{ln ( 2 )} - 1

x = \frac{ln ( 3 )}{ln ( 2 )} - 1

3^{2 x - 1} = 9

e^{4 x} + 4 e^{2 x} - 21 = 0

5 (2^{t}) = 4

\frac{4 ^{x} + 4}{5} = 2^{x}

(4) 5^{3 - x} - 7 = 2