sqrt(3^{2x+1)}=9^{x-2}

Lösung

3^{2 x + 1} = 9^{x - 2}

x = \frac{9}{2}

Dezimale

x = 4.5

Schritte zur Lösung

3^{2 x + 1} = 9^{x - 2}

Wende Exponentenregel an

(2 x + 1) \frac{1}{2} = 2 (x - 2)

Löse

(2 x + 1) \frac{1}{2} = 2 (x - 2) : x = \frac{9}{2}

x = \frac{9}{2}

10 = 2^{x}

3 6^{(3 x - 1)} = 6^{(4 x + 2)}

(- e^{- k} + e^{\frac{- 5 k}{6}}) = 2

2^{2 x} = 16

(e^{4})^{x} e^{x^{2}} = e^{12}