10^{2x^2+2x}=100^{-6x+8}

Lösung

1 0^{2 x^{2} + 2 x} = 10 0^{- 6 x + 8}

x = 1, x = - 8

Schritte zur Lösung

1 0^{2 x^{2} + 2 x} = 10 0^{- 6 x + 8}

Wende Exponentenregel an

2 x^{2} + 2 x = 2 (- 6 x + 8)

Löse

2 x^{2} + 2 x = 2 (- 6 x + 8) : x = 1, x = - 8

x = 1, x = - 8

(2 e)^{(x^{2} - 2)} = 4

- 4 \cdot 3^{6 w} = - 1750

so l v e f or x, e = e^{x y}

\frac{( 2 ^{x} - 2 ^{- x} )}{3} = 4

e^{6 x} = e^{2 x + 1}