4^{(2x^2+x-6)}=1

Lösung

4^{(2 x^{2} + x - 6)} = 1

x = \frac{3}{2}, x = - 2

Dezimale

x = 1.5, x = - 2

Schritte zur Lösung

4^{(2 x^{2} + x - 6)} = 1

Wende Exponentenregel an

(2 x^{2} + x - 6) ln (4) = ln (1)

Löse

(2 x^{2} + x - 6) ln (4) = ln (1) : x = \frac{3}{2}, x = - 2

x = \frac{3}{2}, x = - 2

so l v e f or t, a = p (1 + r)^{t}

(\frac{1}{16})^{x - 2} = 64

10 0^{x + 3} = \frac{1}{10}

2^{x} = 4^{3}

\frac{1}{e ^{x}} = 0