5^{x+1}=10^x

Lösung

5^{x + 1} = 1 0^{x}

x = \frac{ln ( 5 )}{ln ( 2 )}

Dezimale

x = 2.32192 \dots

Schritte zur Lösung

5^{x + 1} = 1 0^{x}

Wende Exponentenregel an

(x + 1) ln (5) = x ln (10)

Löse

(x + 1) ln (5) = x ln (10) : x = \frac{ln ( 5 )}{ln ( 2 )}

x = \frac{ln ( 5 )}{ln ( 2 )}

2^{x + 2} = 8^{- x + 8}

so l v e f or x, 5 (1.08)^{x} = 20

e^{4 - 4 x} = 6

lo g_{2} (x^{l o g_{2} (x)}) = 4

e^{2 x + 1} = 5