2^r=(1/3)^{r-1}

Lösung

2^{r} = (\frac{1}{3})^{r - 1}

r = \frac{ln ( 3 )}{ln ( 6 )}

Dezimale

r = 0.61314 \dots

Schritte zur Lösung

2^{r} = (\frac{1}{3})^{r - 1}

Wende Exponentenregel an

r ln (2) = (r - 1) ln (\frac{1}{3})

Löse

r ln (2) = (r - 1) ln (\frac{1}{3}) : r = \frac{ln ( 3 )}{ln ( 6 )}

r = \frac{ln ( 3 )}{ln ( 6 )}

10 = 2^{\frac{t}{3}}

2 = 1. 2^{x}

5^{5 x + 2} = 15

\frac{e ^{x} + e ^{- x}}{e ^{x} + 1} = 4

4 e^{2 x} - e^{x} = 0