k^3=5

Lösung

k^{3} = 5

k = 35, k = - 35 \frac{1}{2} + 35 \frac{3}{2} i, k = - 35 \frac{1}{2} - 35 \frac{3}{2} i

Schritte zur Lösung

k^{3} = 5

Für

x^{3} = f (a)

sind die Lösungen

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

k = 35, k = 35 \frac{- 1 + 3 i}{2}, k = 35 \frac{- 1 - 3 i}{2}

Vereinfache

35 \frac{- 1 + 3 i}{2} : - 35 \frac{1}{2} + 35 \frac{3}{2} i

Vereinfache

35 \frac{- 1 - 3 i}{2} : - 35 \frac{1}{2} - 35 \frac{3}{2} i

k = 35, k = - 35 \frac{1}{2} + 35 \frac{3}{2} i, k = - 35 \frac{1}{2} - 35 \frac{3}{2} i

x^{4} = 13 x^{2} - 36

0 = 6 x^{2} + 4 x^{3}

- x^{3} + 7 x^{2} + 17 x + 9 = 0

- 3 x^{10} = 5 x - 8

(2 n + 2) (n + 1) (n + 2) = 160