G(x)=sqrt(x^2-9)

解

G (x) = x^{2} - 9

x = - \frac{9}{G ^{2} - 1} {0 \leq G < 1}, x = - - \frac{9}{G ^{2} - 1} {- 1 < G \leq 0}

解答ステップ

G (x) = x^{2} - 9

両辺を2乗する:

G^{2} x^{2} = x^{2} - 9

G^{2} x^{2} = x^{2} - 9

解く

G^{2} x^{2} = x^{2} - 9 : x = - \frac{9}{G ^{2} - 1}, x = - - \frac{9}{G ^{2} - 1}

x = - \frac{9}{G ^{2} - 1}, x = - - \frac{9}{G ^{2} - 1}

解を検算する:

x = - \frac{9}{G ^{2} - 1} {0 \leq G < 1}, x = - - \frac{9}{G ^{2} - 1} {- 1 < G \leq 0}

解答は

x = - \frac{9}{G ^{2} - 1} {0 \leq G < 1}, x = - - \frac{9}{G ^{2} - 1} {- 1 < G \leq 0}