|(x+2)(x-3)|=0

Lösung

∣ (x + 2) (x - 3) ∣ = 0

x = - 2 or x = 3

Schritte zur Lösung

∣ (x + 2) (x - 3) ∣ = 0

Wende Absoluteregel an: Wenn

∣ u ∣ = 0

dann

u = 0

(x + 2) (x - 3) = 0

(x + 2) (x - 3) = 0 : x = - 2, x = 3

x = - 2 or x = 3

∣ y - 2 ∣ = 7

∣ 2 x + 11 ∣ = 7

2 x^{2} - 5 x = 4 - x

\frac{b}{3} = 2

∣ 3 - x ∣ = 0