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人気のある代数 >

(q)=5+10log_{10}(10+2q)

解

(q) = 5 + 10 lo g_{10} (10 + 2 q)

解

q = - \frac{10 W _{- 1} ( - \frac{l n ( 10 )}{200} )}{ln ( 10 )} - 5, q = - \frac{10 W _{0} ( - \frac{l n ( 10 )}{200} )}{ln ( 10 )} - 5

+1

十進法表記

q = 22.38550 \dots, q = - 4.94941 \dots

解答ステップ

(q) = 5 + 10 lo g_{10} (10 + 2 q)

辺を交換する

5 + 10 lo g_{10} (10 + 2 q) = q

5

を右側に移動します

10 lo g_{10} (10 + 2 q) = q - 5

以下で両辺を割る

10

lo g_{10} (10 + 2 q) = \frac{q - 5}{10}

f (x) = g (x)

ならば,

a^{f (x)} = a^{g (x)}

1 0^{l o g_{10} (10 + 2 q)} = 1 0^{\frac{q - 5}{10}}

簡素化

1 0^{l o g_{10} (10 + 2 q)} : 10 + 2 q

10 + 2 q = 1 0^{\frac{q - 5}{10}}

解く

10 + 2 q = 1 0^{\frac{q - 5}{10}} : q = - \frac{10 W _{- 1} ( - \frac{l n ( 10 )}{200} )}{ln ( 10 )} - 5, q = - \frac{10 W _{0} ( - \frac{l n ( 10 )}{200} )}{ln ( 10 )} - 5

q = - \frac{10 W _{- 1} ( - \frac{l n ( 10 )}{200} )}{ln ( 10 )} - 5, q = - \frac{10 W _{0} ( - \frac{l n ( 10 )}{200} )}{ln ( 10 )} - 5

解を検算する:

q = - \frac{10 W _{- 1} ( - \frac{l n ( 10 )}{200} )}{ln ( 10 )} - 5

真

, q = - \frac{10 W _{0} ( - \frac{l n ( 10 )}{200} )}{ln ( 10 )} - 5

真

解答は

q = - \frac{10 W _{- 1} ( - \frac{l n ( 10 )}{200} )}{ln ( 10 )} - 5, q = - \frac{10 W _{0} ( - \frac{l n ( 10 )}{200} )}{ln ( 10 )} - 5

グラフ

人気の例

lo g_{10} (2 x) = 1

1 = lo g_{b} (3)

solvefor y,x=-ln(y-2)

so l v e f or y, x = - ln (y - 2)

ln(x+2)-ln(x-1)=1

ln (x + 2) - ln (x - 1) = 1

log_{10}(x)=4.8

lo g_{10} (x) = 4.8