(a+3i)(1+bi)=25-39i

解答

(a + 3 i) (1 + bi) = 25 - 39 i

(a = 18, b = - \frac{7}{3} a = 7, b = - 6)

求解步骤

(a + 3 i) (1 + bi) = 25 - 39 i

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(a + 3 i) (1 + bi) : (a - 3 b) + i (3 + ab)

(a - 3 b) + i (3 + ab) = 25 - 39 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[a - 3 b = 25 3 + ab = - 39]

[a - 3 b = 25 3 + ab = - 39] : (a = 18, b = - \frac{7}{3} a = 7, b = - 6)

(a = 18, b = - \frac{7}{3} a = 7, b = - 6)

x^{2} - 5 x + (7 + i) = 0

A = p (1 + \frac{i}{100})^{2}

9 x - 18 i = - 36 + 6

2 x - y + (2 x - 3 y - 2 - 9) i = 0

z (t) = - 2 i (1 - t) + 2 i t