vereinfachen (2x^3+4x^2+x-10)-(2x^4-x^3+5x-6)

Lösung

vereinfachen

(2 x^{3} + 4 x^{2} + x - 10) - (2 x^{4} - x^{3} + 5 x - 6)

- 2 x^{4} + 3 x^{3} + 4 x^{2} - 4 x - 4

Schritte zur Lösung

(2 x^{3} + 4 x^{2} + x - 10) - (2 x^{4} - x^{3} + 5 x - 6)

Apply rule:

(a) = a

(2 x^{3} + 4 x^{2} + x - 10) = 2 x^{3} + 4 x^{2} + x - 10

= 2 x^{3} + 4 x^{2} + x - 10 - (2 x^{4} - x^{3} + 5 x - 6)

Wende das Distributivgesetz an:

- (a - b) = - a + b

- (2 x^{4} - x^{3} + 5 x - 6) = - 2 x^{4} + x^{3} - 5 x + 6

= 2 x^{3} + 4 x^{2} + x - 10 - 2 x^{4} + x^{3} - 5 x + 6

Fasse gleiche Terme zusammen

= - 2 x^{4} + 2 x^{3} + x^{3} + 4 x^{2} + x - 5 x - 10 + 6

Addiere gleiche Elemente:

2 x^{3} + x^{3} = 3 x^{3}

= - 2 x^{4} + 3 x^{3} + 4 x^{2} + x - 5 x - 10 + 6

Addiere gleiche Elemente:

x - 5 x = - 4 x

= - 2 x^{4} + 3 x^{3} + 4 x^{2} - 4 x - 10 + 6

Addiere die Zahlen:

- 10 + 6 = - 4

= - 2 x^{4} + 3 x^{3} + 4 x^{2} - 4 x - 4

f a c t or 2 x^{3} + 2 x

f a c t or - 2 x^{2} + 6 x - 4

s im pl i f y \frac{\frac{1}{1}}{3}

f a c t or a^{2} + 17 a + 72

s im pl i f y \frac{1}{E - 0.5} - \frac{1}{E + 1}