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受欢迎的代数 >

-16t^2+80t+50=0

解答

- 16 t^{2} + 80 t + 50 = 0

解答

t = - \frac{5 ( 6 - 2 )}{4}, t = \frac{5 ( 2 + 6 )}{4}

+1

十进制

t = - 0.56186 \dots, t = 5.56186 \dots

求解步骤

- 16 t^{2} + 80 t + 50 = 0

使用求根公式求解

t_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 ( - 16 ) \cdot 50}{2 ( - 16 )}

8 0^{2} - 4 (- 16) \cdot 50 = 406

t_{1, 2} = \frac{- 80 \pm 40 6}{2 ( - 16 )}

将解分隔开

t_{1} = \frac{- 80 + 40 6}{2 ( - 16 )}, t_{2} = \frac{- 80 - 40 6}{2 ( - 16 )}

t = \frac{- 80 + 40 6}{2 ( - 16 )} : - \frac{5 ( 6 - 2 )}{4}

t = \frac{- 80 - 40 6}{2 ( - 16 )} : \frac{5 ( 2 + 6 )}{4}

二次方程组的解是:

t = - \frac{5 ( 6 - 2 )}{4}, t = \frac{5 ( 2 + 6 )}{4}

作图

流行的例子

2 b^{2} + 4 b - 126 = 0

z^2+0.2z-0.08=0

z^{2} + 0.2 z - 0.08 = 0

因式分解 x^2=x+30

f a c t or x^{2} = x + 30

- 3 x^{2} + 15 = 0

n(4+2n)-4(n-6)=74

n (4 + 2 n) - 4 (n - 6) = 74