solvefor x,x^2+sqrt(m)x-m=0

解

x, x^{2} + m x - m = 0

x = \frac{- m + 5 m}{2}, x = \frac{- m - 5 m}{2}

解答ステップ

x^{2} + m x - m = 0

解くとthe二次式

x_{1, 2} = \frac{- m \pm ( m ) ^{2} - 4 \cdot 1 \cdot ( - m )}{2 \cdot 1}

簡素化

(m)^{2} - 4 \cdot 1 \cdot (- m) : 5 m

x_{1, 2} = \frac{- m \pm 5 m}{2 \cdot 1}

解を分離する

x_{1} = \frac{- m + 5 m}{2 \cdot 1}, x_{2} = \frac{- m - 5 m}{2 \cdot 1}

x = \frac{- m + 5 m}{2 \cdot 1} : \frac{- m + 5 m}{2}

x = \frac{- m - 5 m}{2 \cdot 1} : \frac{- m - 5 m}{2}

二次equationの解:

x = \frac{- m + 5 m}{2}, x = \frac{- m - 5 m}{2}