solvefor x,3x^2-2+2sinx=0

解答

求解

x, 3 x^{2} - 2 + 2 sin (x) = 0

x \approx - 1.1263

度数

x = - 64.53223 \dots^{\circ}

求解步骤

3 x^{2} - 2 + 2 sin (x) = 0

Find the interval where both equation sides share the same range:

- \frac{2}{3} \leq x \leq \frac{2}{3}

- \frac{2}{3} \leq x \leq \frac{2}{3}

Find the difference function:

3 x^{2} + 2 sin (x) - 2

3 x^{2} + 2 sin (x) - 2

Extreme points of

3 x^{2} + 2 sin (x) - 2

- \frac{2}{3} \leq x \leq \frac{2}{3}

(- \frac{2}{3}, - 2 sin (\frac{2}{3}) + 2), (- 0.31675, - 2.32196 \dots), (\frac{2}{3}, 2 sin (\frac{2}{3}) + 2)

Find the x-axis intersections

x \approx - 1.1263, x \approx 0.55937

因为方程对以下值无定义:

0.55937

x \approx - 1.1263

so l v e f or x, 6 x^{2} - 18 x = 0

X^{2} + 25 = - 10 X

co m pl e t es q u a re 2 x^{2} - 20 x + 58

co m pl e t es q u a re 3 x^{2} - 6 x + 9

so l v e f or y, x^{2} + y^{4} = 4