solvefor t,y=(1/a-t^2)^{-1}

解

解く

t, y = (\frac{1}{a} - t^{2})^{- 1}

t = i \frac{a - y}{a y}, t = - i \frac{a - y}{a y}; y \neq = 0, a \neq = 0

解答ステップ

y = (\frac{1}{a} - t^{2})^{- 1}

改良

y = \frac{a}{1 - t ^{2} a}

以下で両辺を乗じる:

1 - t^{2} a

y (1 - t^{2} a) = a

解く

y (1 - t^{2} a) = a : t = i \frac{a - y}{a y}, t = - i \frac{a - y}{a y}; y \neq = 0, a \neq = 0

t = i \frac{a - y}{a y}, t = - i \frac{a - y}{a y}; y \neq = 0, a \neq = 0