4^{x^2+1}=2^{5x+5}

Lösung

4^{x^{2} + 1} = 2^{5 x + 5}

x = 3, x = - \frac{1}{2}

Dezimale

x = 3, x = - 0.5

Schritte zur Lösung

4^{x^{2} + 1} = 2^{5 x + 5}

Wende Exponentenregel an

2 (x^{2} + 1) = 5 x + 5

Löse

2 (x^{2} + 1) = 5 x + 5 : x = 3, x = - \frac{1}{2}

x = 3, x = - \frac{1}{2}

x^{3} = 1. 5^{x}

4^{x + 2} - 3 \times 2^{x + 3} = 160

3 (5^{x - 1}) = 21

4 \cdot 1 0^{2 - x} = 15

2^{2 x} + 2^{x} - 56 = 0