1024^{x+1}=16^5

Lösung

102 4^{x + 1} = 1 6^{5}

x = 1

Schritte zur Lösung

102 4^{x + 1} = 1 6^{5}

Wende Exponentenregel an

5 (x + 1) = 10

Löse

5 (x + 1) = 10 : x = 1

x = 1

so l v e f or x, f^{8 x + 11} = a^{9 x + 4}

e^{x} = 21

5^{x - 7} = \frac{1}{125}

5^{x} - 97 \cdot 5^{\frac{x}{2}} + 6^{4} = 0

8 1^{x + 5} = 3^{2 x}