e^{x^2+12}=e^{7x}

Lösung

e^{x^{2} + 12} = e^{7 x}

x = 4, x = 3

Schritte zur Lösung

e^{x^{2} + 12} = e^{7 x}

Wende Exponentenregel an

x^{2} + 12 = 7 x

Löse

x^{2} + 12 = 7 x : x = 4, x = 3

x = 4, x = 3

2 \times 3^{x} + 5 \times 3^{x} - 3^{x} = 6

e^{8 x} + 8 e^{8 x} x = 0

125 = 2 5^{2 h + 1}

2^{(1 + 2 x)} = 32

so l v e f or a, x^{5} 5 x = x^{a}