4^x=9^{x-2}

Lösung

4^{x} = 9^{x - 2}

x = - \frac{2 ln ( 3 )}{ln ( 2 ) - ln ( 3 )}

Dezimale

x = 5.41902 \dots

Schritte zur Lösung

4^{x} = 9^{x - 2}

Wende Exponentenregel an

x ln (4) = (x - 2) ln (9)

Löse

x ln (4) = (x - 2) ln (9) : x = - \frac{2 ln ( 3 )}{ln ( 2 ) - ln ( 3 )}

x = - \frac{2 ln ( 3 )}{ln ( 2 ) - ln ( 3 )}

10 e - 0.0 3^{t} = 4

2^{2 x} = 6

3^{\frac{x}{5}} = 2^{4 x - 2}

2^{x + 1} - 2^{x} = 8

5^{x} + 5^{x + 2} = 650