10^x=49

Lösung

1 0^{x} = 49

x = \frac{2 ln ( 7 )}{ln ( 10 )}

Dezimale

x = 1.69019 \dots

Schritte zur Lösung

1 0^{x} = 49

Wende Exponentenregel an

x ln (10) = ln (49)

Löse

x ln (10) = ln (49) : x = \frac{2 ln ( 7 )}{ln ( 10 )}

x = \frac{2 ln ( 7 )}{ln ( 10 )}

(\frac{1}{2})^{x^{2}} = 3^{x}

1 6^{x^{2} + 1} = 2^{4 x + 7}

7 e^{7 x} - e^{- x} = 0

x e^{- x} - 2 e^{- x} = 0

1 3^{x} = 4