4x^3+12x^2-4x=0

Lösung

4 x^{3} + 12 x^{2} - 4 x = 0

x = 0, x = \frac{- 3 + 13}{2}, x = \frac{- 3 - 13}{2}

Dezimale

x = 0, x = 0.30277 \dots, x = - 3.30277 \dots

Schritte zur Lösung

4 x^{3} + 12 x^{2} - 4 x = 0

Faktorisiere

4 x^{3} + 12 x^{2} - 4 x : 4 x (x^{2} + 3 x - 1)

4 x (x^{2} + 3 x - 1) = 0

Anwendung des Nullfaktorprinzips: Wenn

ab = 0

dann

a = 0

oder

b = 0

x = 0 or x^{2} + 3 x - 1 = 0

Löse

x^{2} + 3 x - 1 = 0 : x = \frac{- 3 + 13}{2}, x = \frac{- 3 - 13}{2}

Die Lösungen sind

x = 0, x = \frac{- 3 + 13}{2}, x = \frac{- 3 - 13}{2}

x^{6} - 14 x^{4} + 3 x^{2} - 42 = 0

x^{4} - x^{3} - 13 x^{2} + x + 12 = 0

s^{3} + 10.6 s^{2} + 7 s + 10 = 0

200 x - 0.02 x^{2} - 0.000002 x^{3} - 80000 = 0

2 x^{3} - 14 x^{2} + 2 x - 14 = 0