k^2-3k=0

解

k^{2} - 3 k = 0

k = 3, k = 0

解答ステップ

k^{2} - 3 k = 0

解くとthe二次式

k_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

k_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

解を分離する

k_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, k_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

k = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

k = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

二次equationの解:

k = 3, k = 0