化简 ((2n+1)!)/((2n+2)!)

解答

化简

\frac{( 2 n + 1 ) !}{( 2 n + 2 ) !}

\frac{1}{2 n + 2}

求解步骤

\frac{( 2 n + 1 ) !}{( 2 n + 2 ) !}

消去因子:

\frac{n !}{( n + m ) !} = \frac{1}{( n + 1 ) \cdot ( n + 2 ) \dots ( n + m )}

\frac{( 2 n + 1 ) !}{( 2 n + 2 ) !} = \frac{1}{( 2 n + 2 )}

= \frac{1}{2 n + 2}

f a c t or 81 + 30.25

- 24 \leq 4 x - 11 \leq 1

6 x^{2} = 5 x + 6

2 + 3 x \leq - 7

5 x + 6 = 2 + 3 x