(x+3)^2+7(x+3)-18=0

解

(x + 3)^{2} + 7 (x + 3) - 18 = 0

x = - 1, x = - 12

解答ステップ

(x + 3)^{2} + 7 (x + 3) - 18 = 0

拡張

(x + 3)^{2} + 7 (x + 3) - 18 : x^{2} + 13 x + 12

x^{2} + 13 x + 12 = 0

解くとthe二次式

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot 12 = 11

x_{1, 2} = \frac{- 13 \pm 11}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 13 + 11}{2 \cdot 1}, x_{2} = \frac{- 13 - 11}{2 \cdot 1}

x = \frac{- 13 + 11}{2 \cdot 1} : - 1

x = \frac{- 13 - 11}{2 \cdot 1} : - 12

二次equationの解:

x = - 1, x = - 12