y^'-y/x =0

Lösung

y^{^{'}} - \frac{y}{x} = 0

y = c_{1} x

Schritte zur Lösung

y^{'} (x) - \frac{y}{x} = 0

Solve separable ODE:

y = c_{1} x

y = c_{1} x

\int (4 x + 3) \cdot (2 x^{2} + 3 x)^{3} d x

\int \frac{( x ^{3} )}{x ^{2} + 64} d x

t an g e n t y = x^{3} - 2 x + 1, (3, 22)

t a y l or (- 3 x + 14)^{\frac{4}{3}}, 2

\frac{\partial}{\partial x} (x^{5} + x^{2} y + x + 1)