derivative 2sin^3(t)

解答

导数

2 sin^{3} (t)

6 sin^{2} (t) cos (t)

求解步骤

\frac{d}{d t} (2 sin^{3} (t))

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (sin^{3} (t))

使用连锁律:

3 (sin (t))^{2} \frac{d}{d t} (sin (t))

= 3 (sin (t))^{2} \frac{d}{d t} (sin (t))

\frac{d}{d t} (sin (t)) = cos (t)

= 2 \cdot 3 (sin (t))^{2} cos (t)

化简

= 6 sin^{2} (t) cos (t)

x \to - 6 lim (\frac{( x ^{2} - 36 )}{x + 6})

d er i v a t i v e 4 x - 16

\int \frac{4}{x ^{3}} d x

d er i v a t i v e ln (t + 1)

\frac{\partial}{\partial x} (7 ln (\frac{3 x y}{7 z}))