integral of e^t-1

Lösung

\int e^{t} - 1 d t

e^{t} - t + C

Schritte zur Lösung

\int e^{t} - 1 d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{t} d t - \int 1 d t

\int e^{t} d t = e^{t}

\int 1 d t = t

= e^{t} - t

Füge eine Konstante zur Lösung hinzu

= e^{t} - t + C

\int_{- 6}^{6} (e^{x} - e^{- x})^{2} d x

d er i v a t i v e \frac{cos ( t )}{t ^{7}}

\frac{\partial}{\partial b} (\frac{ab}{2 c + 15})

x \to 0 lim (x e^{2 x})

a re a y = 3 (x^{3} - x), y = 0