inverselaplace (e^{-s})/(s^5)

Lösung

inverse laplace transformation

\frac{e ^{- s}}{s ^{5}}

\frac{H ( t - 1 ) ( t - 1 ) ^{4}}{24}

Schritte zur Lösung

L^{- 1} {\frac{e ^{- s}}{s ^{5}}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {e^{- a s} F (s)} = H (t - a) f (t - a)

H (t)

Heaviside (Schritt) Funktion ist

= H (t - 1) L^{- 1} {\frac{1}{s ^{5}}} (t - 1)

L^{- 1} {\frac{1}{s ^{5}}} : \frac{t ^{4}}{24}

= H (t - 1) \frac{( t - 1 ) ^{4}}{24}

= \frac{H ( t - 1 ) ( t - 1 ) ^{4}}{24}

x \to 0 lim (\frac{( 4 ^{x} - 1 )}{x})

\int sin (7 x - 10) d x

x \to \infty lim (4 x^{3})

\frac{\partial}{\partial y} (ln (\frac{x ^{2}}{y}))

\frac{d}{d x} (\frac{4}{9} x^{3})