derivative of 8/x-2/(x^3+1/(x^4))

Lösung

\frac{d}{d x} (\frac{8}{x} - \frac{2}{x ^{3}} + \frac{1}{x ^{4}})

- \frac{8}{x ^{2}} + \frac{6}{x ^{4}} - \frac{4}{x ^{5}}

Schritte zur Lösung

\frac{d}{d x} (\frac{8}{x} - \frac{2}{x ^{3}} + \frac{1}{x ^{4}})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{8}{x}) - \frac{d}{d x} (\frac{2}{x ^{3}}) + \frac{d}{d x} (\frac{1}{x ^{4}})

\frac{d}{d x} (\frac{8}{x}) = - \frac{8}{x ^{2}}

\frac{d}{d x} (\frac{2}{x ^{3}}) = - \frac{6}{x ^{4}}

\frac{d}{d x} (\frac{1}{x ^{4}}) = - \frac{4}{x ^{5}}

= - \frac{8}{x ^{2}} - (- \frac{6}{x ^{4}}) - \frac{4}{x ^{5}}

Vereinfache

= - \frac{8}{x ^{2}} + \frac{6}{x ^{4}} - \frac{4}{x ^{5}}

x^{2} y^{^{''}} + 4 x y^{^{'}} + 2 y = 0

x \to 8 lim (x + 8)

x \to \infty lim (ln (2))

n = 0 \sum \infty (\frac{2}{e})^{n}

e x p an d (x^{2} + 4)^{5}