y^'=((e^{(x/3)}+y))/2

Lösung

y^{^{'}} = \frac{( e ^{(\frac{x}{3})} + y )}{2}

y = - 3 e^{\frac{x}{3}} + c_{1} e^{\frac{x}{2}}

Schritte zur Lösung

y^{'} (x) = \frac{( e ^{(\frac{x}{3})} + y )}{2}

Solve linear ODE:

y = - 3 e^{\frac{x}{3}} + c_{1} e^{\frac{x}{2}}

y = - 3 e^{\frac{x}{3}} + c_{1} e^{\frac{x}{2}}

x \to 0 lim (\frac{x}{1 + x})

a re a x^{2} - 6, 3

d er i v a t i v e f (x) = - 2 x^{4} + x^{- 2} - 3 x^{\frac{3}{4}}

t a y l or cos (π - 7 x)

\int_{0}^{3} x^{\frac{1}{2}} d x