(dy)/(dx)y=(sec(x))/(1+sec(x))

Lösung

\frac{d y}{d x} y = \frac{sec ( x )}{1 + sec ( x )}

y = 2 tan (\frac{x}{2}) + c_{1}, y = - 2 tan (\frac{x}{2}) + c_{1}

Schritte zur Lösung

\frac{d y}{d x} y = \frac{sec ( x )}{1 + sec ( x )}

Solve separable ODE:

y = 2 tan (\frac{x}{2}) + c_{1}, y = - 2 tan (\frac{x}{2}) + c_{1}

y = 2 tan (\frac{x}{2}) + c_{1}, y = - 2 tan (\frac{x}{2}) + c_{1}

\int_{0}^{1} \frac{x}{( 2 x + 1 ) ^{3}} d x

\int \frac{1}{x ^{\frac{8}{9}} ( 8 + x ^{\frac{1}{9}} )} d x

\int 4 x^{2} sec (5 x^{3}) d x

\int_{0}^{\frac{π}{4}} 3 tan^{3} (x) d x

\frac{\partial}{\partial z} (e^{3 x + 4 y} cos (5 z))