y^'+(3y)/x =-1/x

Lösung

y^{^{'}} + \frac{3 y}{x} = - \frac{1}{x}

y = \frac{c _{1}}{3 x ^{3}} - \frac{1}{3}

Schritte zur Lösung

y^{'} (x) + \frac{3 y}{x} = - \frac{1}{x}

Solve separable ODE:

y = \frac{c _{1}}{3 x ^{3}} - \frac{1}{3}

y = \frac{c _{1}}{3 x ^{3}} - \frac{1}{3}

\frac{\partial}{\partial x} (2 x^{3} + x y^{2})

\frac{1}{x} \frac{d y}{d x} = e^{x + y}

\frac{d}{d x} (\frac{1}{2 x ln ( x ) + 1})

\int cot^{3} (x) \cdot csc^{3} (x) d x

n = 1 \sum \infty \frac{2 n !}{n ^{n}}