integral of x^2-3x+4

Lösung

\int x^{2} - 3 x + 4 d x

\frac{x ^{3}}{3} - \frac{3 x ^{2}}{2} + 4 x + C

Schritte zur Lösung

\int x^{2} - 3 x + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 3 x d x + \int 4 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 3 x d x = \frac{3 x ^{2}}{2}

\int 4 d x = 4 x

= \frac{x ^{3}}{3} - \frac{3 x ^{2}}{2} + 4 x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{3}}{3} - \frac{3 x ^{2}}{2} + 4 x + C

x \to 0 + lim (sin (x) ln (7 x))

\int \frac{e ^{x} - 4 e ^{- x}}{e ^{x}} d x

y^{3} - (10 x + 2) + 3 x y^{2} \frac{d y}{d x} = 0

\frac{\partial}{\partial x} (x e^{y} + y + 1)

\frac{\partial}{\partial y} (\frac{x ^{2} - y ^{2}}{2})