y^'=4-9^2-6x^5

Lösung

y^{^{'}} = 4 - 9^{2} - 6 x^{5}

y = - x^{6} - 77 x + c_{1}

Schritte zur Lösung

y^{'} (x) = 4 - 9^{2} - 6 x^{5}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 4 - 9^{2} - 6 x^{5} d x

\int 4 - 9^{2} - 6 x^{5} d x = - x^{6} - 77 x + c_{1}

y = - x^{6} - 77 x + c_{1}

\frac{d}{d x} (\frac{1}{4 x ^{5}})

\int_{0}^{6} 36 - x^{2} d x

\int \frac{33}{33 + e ^{x}} d x

\int \frac{( x ^{2} - 1 )}{x} d x

\frac{d}{d x} (ln (x^{2} + 1) - e^{\frac{x}{2}} cos (π x))